cregit-Linux how code gets into the kernel

Release 4.14 arch/microblaze/include/asm/hash.h

/* SPDX-License-Identifier: GPL-2.0 */
#ifndef _ASM_HASH_H

#define _ASM_HASH_H

/*
 * Fortunately, most people who want to run Linux on Microblaze enable
 * both multiplier and barrel shifter, but omitting them is technically
 * a supported configuration.
 *
 * With just a barrel shifter, we can implement an efficient constant
 * multiply using shifts and adds.  GCC can find a 9-step solution, but
 * this 6-step solution was found by Yevgen Voronenko's implementation
 * of the Hcub algorithm at http://spiral.ece.cmu.edu/mcm/gen.html.
 *
 * That software is really not designed for a single multiplier this large,
 * but if you run it enough times with different seeds, it'll find several
 * 6-shift, 6-add sequences for computing x * 0x61C88647.  They are all
 *      c = (x << 19) + x;
 *      a = (x <<  9) + c;
 *      b = (x << 23) + a;
 *      return (a<<11) + (b<<6) + (c<<3) - b;
 * with variations on the order of the final add.
 *
 * Without even a shifter, it's hopless; any hash function will suck.
 */

#if CONFIG_XILINX_MICROBLAZE0_USE_HW_MUL == 0


#define HAVE_ARCH__HASH_32 1

/* Multiply by GOLDEN_RATIO_32 = 0x61C88647 */

static inline u32 __attribute_const__ __hash_32(u32 a) { #if CONFIG_XILINX_MICROBLAZE0_USE_BARREL unsigned int b, c; /* Phase 1: Compute three intermediate values */ b = a << 23; c = (a << 19) + a; a = (a << 9) + c; b += a; /* Phase 2: Compute (a << 11) + (b << 6) + (c << 3) - b */ a <<= 5; a += b; /* (a << 5) + b */ a <<= 3; a += c; /* (a << 8) + (b << 3) + c */ a <<= 3; return a - b; /* (a << 11) + (b << 6) + (c << 3) - b */ #else /* * "This is really going to hurt." * * Without a barrel shifter, left shifts are implemented as * repeated additions, and the best we can do is an optimal * addition-subtraction chain. This one is not known to be * optimal, but at 37 steps, it's decent for a 31-bit multiplier. * * Question: given its size (37*4 = 148 bytes per instance), * and slowness, is this worth having inline? */ unsigned int b, c, d; b = a << 4; /* 4 */ c = b << 1; /* 1 5 */ b += a; /* 1 6 */ c += b; /* 1 7 */ c <<= 3; /* 3 10 */ c -= a; /* 1 11 */ d = c << 7; /* 7 18 */ d += b; /* 1 19 */ d <<= 8; /* 8 27 */ d += a; /* 1 28 */ d <<= 1; /* 1 29 */ d += b; /* 1 30 */ d <<= 6; /* 6 36 */ return d + c; /* 1 37 total instructions*/ #endif }

Contributors

PersonTokensPropCommitsCommitProp
George Spelvin170100.00%1100.00%
Total170100.00%1100.00%

#endif /* !CONFIG_XILINX_MICROBLAZE0_USE_HW_MUL */ #endif /* _ASM_HASH_H */

Overall Contributors

PersonTokensPropCommitsCommitProp
George Spelvin19399.48%150.00%
Greg Kroah-Hartman10.52%150.00%
Total194100.00%2100.00%
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